J.R. S. answered 02/18/19
Ph.D. University Professor with 10+ years Tutoring Experience
Recall that at STP the volume of 1 mole of any ideal gas will be 22.4 liters. Put another way, 22.4 L = 1 mol.
3 L x 1 mole/22.4 L = 0.134 moles O2 gas. Since the molar mass of O2 = 32g/mole, we have...
0.134 moles x 32 g/mole = 4.29 g = 4 g (to 1 significant figure)