J.R. S. answered 02/18/19
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat = ?
m = mass of water (not of the chips) = 58.18 g
C = specific heat of water = 4.184 J/g-deg
∆T = change in temperature = 28.1 - 21.5 = 6.6 deg
q = (58.18 g)(4.284 J/g-deg)(6.6 deg) = 1607 J of energy absorbed by the water