How many grams of NH3 can be produced from 11.2 g of H2?

Answer 1

Balanced equation: N₂ + 3H₂ ==> 2NH₃

moles H₂ used = 11.2 g x 1 mole H₂/2 g = 5.6 moles

moles NH₃ produced = 5.6 moles H₂ x 2 moles NH₃/3 moles H₂ = 3.73 moles NH₃

grams NH₃ = 3.73 moles NH₃ x 17 g/mole NH₃ = 63.5 g NH₃