what is the mass of carbon dioxide if 5.00 grams of propane are consumed in the following reaction

Question

c3h8+5o2=3co2+4h2o

please help please help

Answer 1

Balanced equation: C3H8 + 5O2 ==> 3CO2 + 4H2O

moles of propane used = 5.00 g x 1 mole/44g = 0.1136 moles

moles of CO2 produced = 0.1136 moles propane x 3 moles CO2/mole propane = 0.3409 moles CO2

mass of CO2 = 0.3409 moles CO2 x 44 g/mole = 15.0 g CO2 (3 sig. figs.)