365 General Admission tickets
432 Student Admission tickets
Systems of Equations will work for this situation
Let x = non students
Let y = students
Equation 1 can represent the total number of people 181
x + y = 181
Equation 2 can represent the total cost $797
5x + 4y = 797
Equation 1 is ideal for setting up a substitution
x + y = 181
y = 181 - x
We will substitute this quantity for y in Equation 2
5x + 4y = 797
5x + 4(181 - x) = 797
5x + 724 -4x =797
Combine like terms
x + 724 = 797
Subtract 724 from both sides of the equation
x = 73
We can substitute our value for x in either equation to solve for y
x + y = 181
73 + y = 181
We already y = 181-x = 181- 73= 108
y = 108
We can use our values in both equations to check the values
73 + 108 = 181
5(73) + 4(108) = 797
365 + 432 = 797
Of course this can be done by elimination as another check. Give it a try.
I hope you find this useful.
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