i really need help pls

Question

a triangel. side 1: x

side 2: x+2

side Pythagoras: 2x

Area= (3+2√3)

Question: Show that the area is (3+2√3)

Answer 1

(2x)^2 = x^2 + (x+2)^2

4x^2 = 2x^2 + 4x +4

2x^2 -4x -4 = 0

x^2 -2x -2 = 0

x = 2/2 + (.5)(sqr(4 +8) = 1 + sqr3 = one leg's length

x+2 = 3 +sqr3 = second leg's length

Area = (1+sqr3)(3+sqr3)/2 = (3 +4sqr3 +3)/2 = (6+4sqr3)/2 = 3+2sqr3