An ideal gas with an initial volume of 4.07 L is cooled at constant pressure to 25.0 °C where its final volume is 3.41 L. What was the temperature initially (in degrees Celsius)?

Answer 1

This gas problem is at constant pressure so Charles' Law is appropriate.

V1/T1 = V2/T2

V1 = 4.07 L

T1 = ?

V2 = 3.41 L

T2 = 25.0ºC + 273 = 298K

(4.07 L)/(T1) = (3.41 L)/(298K)

T1 = 356K

T1 = 356K - 273 = 82.7ºC