25 L of gas at 0.15 ATM and 50°C returns to standard conditions. What is the new volume

Answer 1

Standard conditions: P = 1 atm; T = 273K

So ee have

P1 = 0.15 atm

V1 = 25 L

T1 = 50 + 273 = 323K

P2 = 1atm

V2 = ?

T2 = 273K

Using P1V1/T1 = P2v2/T2 plug in the values and solve for V2