Urn 1 contains 6 red balls and 4 black balls. Urn 2

Question

Urn 1 contains 6 red balls and 4 black balls. Urn 2 contains 4 red balls and 6 black balls. Urn 3 contains 4 red balls and 5 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red.

Answer 1

(1/3)(.6 + .4 + .44444444) = .481