J.R. S. answered 02/12/19
Ph.D. University Professor with 10+ years Tutoring Experience
2KOH + H2SO4 ==> K2SO4 + 2H2O ... balanced equation
moles KOH used = 0.025 L x 0.150 mol/L = 0.00375 moles
moles H2SO4 = 0.00375 mol KOH x 1 mol H2SO4/2 mol KOH = 0.001875 moles H2SO4 present
Concentration H2SO4 = 0.001875 moles/0.015L = 0.125 M