J.R. S. answered 02/11/19
Ph.D. University Professor with 10+ years Tutoring Experience
Constant temperature = Boyles Law
P1V1 = P2V2
(6.85 atm)(9.00 L) = (6.21 atm)(P2)
P2 = ((6.85)(9.00)/(6.21)
P2 = 9.93 atm
Krystina A.
asked 02/11/19Suppose a sample of helium at 20 degrees Celsius occupies a volume of 9.00 L at a pressure of 6.85 atm. What volume does this helium sample occupy if the pressure is reduced to 6.21 atm while maintaining the temperature at 20 degrees Celsius
J.R. S. answered 02/11/19
Ph.D. University Professor with 10+ years Tutoring Experience
Constant temperature = Boyles Law
P1V1 = P2V2
(6.85 atm)(9.00 L) = (6.21 atm)(P2)
P2 = ((6.85)(9.00)/(6.21)
P2 = 9.93 atm
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