What is the pressure of 1.9 mols of nitrogen gas in a 9.45 L tank and at a temperature of 228K

Answer 1

PV = nRT ... Ideal gas law

P = ?

V = 9.45 L

n = 1.9 moles

R = 0.0821 Latm/Kmol

T = 228K

P = nRT/V = (1.9)(0.0821)(228)/(9.45) = 3.76 atm