What will be the freezing point of a solution that contains 60.5g of glucose (C6H12O6) in 555g of water? Use Kf=1.86∘Cm.

Question

What will be the freezing point of a solution that contains 60.5g of glucose (C6H12O6) in 555g of water?

1. Use Kf=1.86∘C/m.

Answer 1

Colligative properties:

∆T = imK

∆T = change in freezing point temperature = ?

i = van't Hoff factor = 1 for glucose since it is a non electrolyte and does not dissociate or ionize

m = molality = moles glucose/kg solvent: 60.5 g x 1 mol/180 g = 0.336 moles/0.555 kg = 0.606 m

k = freezing constant = 1.86 degrees/m

∆T = (1)(0.606)(1.86) = 1.13 degrees

Freezing point of solution = 0º - 1.13º = -1.13ºC