A student reacts 100g of carbon in the lab and gets a 75% yield of carbon monoxide. What is the actual yield in grams?

Answer 1

2C + O₂(g) ==> 2CO(g) ... balanced equation

moles of C used = 100 g C x 1 mole C/12 g = 8.33 moles of C

Theoretical yield of CO = 8.33 mole C x 2 mole CO/2 mole C = 8.33 moles CO x 28 g CO/mol CO = 233 g

Actual yield is 75% of the theoretical yield, so actual yield = 0.75 x 233 g = 175 g