A gas occupies 3.39 L when the temperature is 45.0°C and at 1.00 atm of pressure. What temperature change (in K) will be needed to change the volume to 6.35 L at constant pressure?

Question

A gas occupies 3.39 L when the temperature is 45.0°C and at 1.00 atm of pressure. What temperature change (in K) will be needed to change the volume to 6.35 L at constant pressure? 

Answer 1

When pressure is constant, we use Charles Law:

V1/T1 = V2/T2

V1 = 3.39 L

T1 = 45.0ºC + 273 = 318K

V2 = 6.35 L

T2 = ?

3.39/318 = 6.35/T2

T2 = (6.35)(318)/3.39

T2 = 596K

So, the change in temperature = 596K - 318K = 278K