J.R. S. answered 02/05/19
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat = 86 J
m = mass = 17 g
C = specific heat = 0.128 J/g-degree
∆T = change in temperature
86 J = (17 g)(0.128 J/g-degree)(∆T)
∆T = 86 J/(17 g)(0.128 J/g-degree)
∆T = 39.5 degrees = +40ºC (it is a positive change in temperature since heat is added to the gold)