J.R. S. answered 02/01/19
Ph.D. University Professor with 10+ years Tutoring Experience
The answer to this question will depend on the initial temperature of the water when the 150 kJ of heat energy is added to it. If we assume that the water is at 100ºC, then we can proceed as follows:
q = m∆Hvap
150 kJ = (m)44.01 kJ/mole)
m = 150 kJ/44.01 kJ/mole
m = 3.41 moles x 18 g/mole = 61.3 g
Since the density is assumed to be 1 g/ml, the answer would be 61.3 mls of water.