If 30.0g of sodium chloride are reacted with excess sulfuric acid , how many grams of sodium sulfate are produced? NaCl + H2SO4 = Na2SO4 + HCl

Answer 1

2NaCl + H₂SO₄ ==> Na₂SO₄ + 2HCl

This would be the balanced equation IF this reaction actually took place. But it doesn't. However, we will proceed with the calculations as if this reaction could take place.

moles NaCl present = 30.0 g x 1 mole NaCl/58.44 g = 0.5133 moles NaCl

moles Na₂SO₄ produced = 0.5133 moles NaCl x 1 moles Na₂SO₄/2 moles NaCl = 0.2567 moles Na₂SO₄

grams Na₂SO₄ produced = 0.2567 moles Na₂SO₄ x 142.0 g/mole = 36.4 g (to 3 sig. figs.)