Lauri L. answered 02/02/19
Algebra 1 Teacher and Tutor: Experienced, Knowledgeable and Patient!
X. .06. .06x
Y. .03. .03y
21 .05 21*.05=1.05
x + y = 21
.06x + .03y = 1.05
2 equations , 2 unknowns solve with substitution or elimination!
Lauri L. answered 02/02/19
Algebra 1 Teacher and Tutor: Experienced, Knowledgeable and Patient!
X. .06. .06x
Y. .03. .03y
21 .05 21*.05=1.05
x + y = 21
.06x + .03y = 1.05
2 equations , 2 unknowns solve with substitution or elimination!
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