You decide that you want to make a sample of A12o3 with a mass of 450.0 grams. How many grams of A1 would you need and how many grams of O2 would you need?

Answer 1

Wow! I almost passed this up because in all my years of chemistry I've never seen A12o3 or A1. Then I realized it was supposed to be aluminum oxide (Al₂O₃) and aluminum (Al).

The reaction would be 4Al(s) + 3O₂(g) ==> 2Al₂O₃(s) ... balanced equation

grams Al needed = 450.0 g Al₂O₃ x 1 mole/101.96 g x 4 mole Al/2 moles Al₂O₃ x 26.98 g/mole Al =

238.2 g Al