Alexa P.

asked • 02/01/19

Chemistry help need by 10:00pm!!!!!!!!

An underground cavern contains 2.24×10^6 liters of methane gas at a pressure of 1.50×10^3 kPa and a temperature of 315 Calvin. How many grams of CH4 are in the cavern?

  1. Put pressure in atm
  2. answer for moles
  3. grams

WITH UNITS so I know which answer is which!!!

1 Expert Answer

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J.R. S. answered • 02/01/19

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Not much time to answer. I’m on an ipad so not easy.

PV = nRT

P = 1.5x103 kPa x 1 atm/101.3kPa = 14.8 atm

V = 2.24x106 L

n = moles = ?

R = 0.0821 Laym/Kmole

T = 315K


plug these values into PV = nRT and solve for n (moles)

to convert to grams multiply the moles by 16, the molar mass of methane

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Alexa P.

Would the moles then be 1.2 x 10^6? Then grams be 1.9 x 10^7?
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02/01/19

Alexa P.

Thank you so much!
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02/01/19

J.R. S.

tutor
Yep. Or1.3x10^6 and 2x10^7 depending on rounding
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02/01/19

Alexa P.

Thank you so much! Now I actually understand it. I will tell my friends about you!
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02/01/19

Alexa P.

I didn’t realize I was being graded on this so would the answers be Did u get? •14.8 atm •1.3x10^6 moles •2x10^7 grams
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02/01/19

J.R. S.

tutor
Sorry for the delay. I must have gone to sleep. It's probably too late for your assignment, but the correct answers would be 14.8 atm; 1.28x10^6 moles and 2.05x10^7 grams (all to 3 significant figures)
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02/01/19

J.R. S.

tutor
Just looked over the explanation and found an error probably because I was rushing to try to get you the answer in time. The conversion of kPa to atm should be 1.5x10^3 kPa x 1 atm/101.3 kPa = 14.8 atm. So, I wrote down the correct value for atm, but wrote the conversion incorrectly. Hope you understand what I'm saying. I'll try to edit my original response for anyone who may look at it. Sorry.
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02/01/19

Alexa P.

Thank you so much! You are the best! I got it right! I am going to tell all my friends about you!
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02/02/19

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