describe how to determine the mass of Mg in the following chemical reaction Mg (s) + (excess) HCl (aq) --> H2 (g) + MgCl2 (aq)

Question

Please do it based on the experimental measurements (related to H₂ ); include all formulas in analysis in or converted to grams.

Answer 1

It would help if you provided some actual data or additional information. The following explanation is based on general concepts and will not include specific values as none were provided.

The balanced equation is Mg(s) + 2HCl(aq) ==> H₂(g) + MgCl₂(aq)

To find the mass of Mg that was consumed in the experiment after measuring/knowing the amount of H₂ gas that was produced you do the following:

Take the moles of H₂ gas produced and divide it by 2 to get moles of Mg used up. Then, multiply that number of moles of Mg by the atomic mass of Mg to obtain grams of Mg consumed.

If the H₂ is given in volume instead of moles, you need to find moles but for that you need the temperature and pressure. After using the gas law to find moles of H2, proceed as above to find moles Mg, and then g of Mg.