chemistry question

Question

The heat of vaporization of water is 40.66 kJ/mol. How much heat is absorbed when 2.38 g of water boils at atmospheric pressure?

Answer 1

q = (m)(delta H)

m = 2.38 g

delta H = 40.66 kJ/mole x 1 mol/18 g = 2.26 kJ/g

q = (2.38 g)(2.26 kJ/g) = 5.38 kJ of heat