Hi Angel. In order to answer this question, we should first:
let b represent the books that cost 3 dollars
let o represent the other books that cost 5 dollars
Now we can set up our system of equations.
The first equation represents the total number of books.
b+o=80
The second equation represents the total price of the books
3b+5o= $300
We must isolate one variable in the first equation, or move the other variable to the right side of the equation. If we choose to find b, we must move the o variable to the right side of the equation.
b+o=80
b=80-o
We now know that b=80-o. We can plug this into the second equation as the value of b and solve for o.
3b+5o=$300
3(80-o)+5o=$300
240-3o+5o=$300; distributed 3 or multiplied each term in the parentheses by 3
240+2o=$300;combined like terms, which were -3o and 5o
2o= 60; subtracted 240 from both sides of the equation
o=30
We now know that o is equal to 30. we can now find the value of b by plugging this value into the first equation and solving for b.
b+30=80
b = 50; subtracted 30 from both sides
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