J.R. S. answered 01/21/19
Ph.D. University Professor with 10+ years Tutoring Experience
Cu(s)+2AgNO3(aq)→Cu(NO3)2(aq)+2Ag(s)
From this balanced equation you see that 1 MOLE of Cu produces 2 MOLES of silver. Assuming that the AgNO3 is not in limiting supply, you can approach this problem as follows.
Moles of Ag produced = 1.80 g Ag x 1 mole/108 g = 0.0167 moles
Moles Cu needed = 0.0167 moles Ag x 1 mol Cu/2 mol Ag = 0.00833 moles Cu
Mass of Cu needed = 0.00833 moles Cu x 63.5 g/mol = 0.529 g Cu