J.R. S. answered 01/21/19
Ph.D. University Professor with 10+ years Tutoring Experience
2Zn(s)+O2(g)⟶ 2 ZnO(s)
2.00 g ZnO x 1 mole/81.4 g = 0.5535 moles ZnO
moles O2 needed = 0.5535 mol ZnO x1 mol O2/2 mol ZnO = 0.2768 moles O2
Mass O2 = 0.2768 moles x 32 g/mol = 8.86 g O2 needed
This is assuming Zn is not limiting and is given to 3 sig figs.