David M. answered 01/21/19
Dave "The Math Whiz"
Two lines that are parallel have the same slope. In the slope-intercept form of line an equation looks like y=mx+b, where m is the slope, b is the y-intercept and x and y are the coordinates of any point on that line. So, the first thing we need to do is put our given equation into the y=mx+b form:
3x+2y=14 original equation
2y=-3x+14 subtract 3x from both sides to isolate the y term
y=(-3/2)x+14/2 divide both sides by 2 to isolate y
y=(-3/2)x+7 simplify
Now we know that the slope, m, of this equation is -3/2 which will be the same for our new equation because they are parallel. The point-slope form of a line is (y-y1)=(x-x1)m, where m is the slope, -3/2, and x1 and y1 are the coordinates of any point on that line. In our case we have a point with coordinates (-4,4), so x1=-4 and y1=4. Put this information into our formula and we get:
(y-4)=(x-(-4))(-3/2)
y-4=(-3/2)(x+4)
y-4=(-3/2)x+(-3/2)(4)
y-4=(-3/2)x-6
y=(-3/2)x-6+4
y=(-3/2)x-2
This is correct, however, most times we want to have the equation in the same form as the other one, that is Ax+By=C, where A, B and C are not fractions. First, multiply everything by 2 to eliminate the slope as a fraction:
y=(-3/2)x-2 our equation
2y=-3x-4 multiply everything by 2 to get rid of the fraction
3x+2y=-4 add 3x to both sides to get our answer
Our new line has the equation 3x+2y=-4.