
Philip P. answered 11/03/14
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Let q = the number of quarters and d = the number of dimes
A collection of quarters and dimes is worth more than $20:
($0.25)*q + ($0.10)*d > $20
There are twice as many quarters as dimes:
q = 2d
Since q = 2d, let's substitute 2d in place of q in the first equation:
($0.25)*q + ($0.10)*d > $20
($0.25)*(2d) + ($0.10)*d > $20 [Substituted 2d for q]
0.50d + 0.10d > 20
0.6d > 20
d > 20/0.6
Solve for d. Since d must be an integer, round decimal values up to the next integer.