What is the equation of a line that passes through the point (6,1) and is perpendicular to the line whoes equation is y=-2I-6

Answer 1

Presumably you mean y = -2x-6.

The slope of the line perpendicular to the line given by y = -2x-6 is 1/2

1/2 = (y-1)/(x-6) is the equation you want and it can be "massaged" into whatever form is required.