J.R. S. answered 01/11/19
Tutor
5.0
(145)
Ph.D. University Professor with 10+ years Tutoring Experience
q = mCdeltaT
q = (34.4 g)(2.44 J/g/deg)(78.8-25) = 83,936 J (83.9 kJ)
(this calculation assumes the units for specific heat are J/g-deg)