J.R. S. answered 01/10/19
Ph.D. University Professor with 10+ years Tutoring Experience
Balanced equation
2H3PO4 + 3Ca(OH)2 ==> Ca3(PO4)2 + 6H2O
moles Ca(OH)2 = 0.0287 L x 0.125 mol/L = 0.003588 moles
moles H3PO4 = .003588 mol x 2/3 = .002392 moles
[H33PO4 = 0.002392 moles/0.025 L = 0.09567 M = 0.096 M