J.R. S. answered 01/09/19
Ph.D. University Professor with 10+ years Tutoring Experience
a). 4C3H5(NO3)3 ==> 12CO2 + 6N2 + 10H2O + O2
b). 10.00 g x 1 mole/227.09 g = 0.04404 moles nitroglycerin
0.04404 moles nitro x 12 mol CO2/4 moles nitro = 0.1321 mol CO2
mass CO2 = 0.1321 moles x 44 g/ mole = 5.813 g (4 sig. figs.)