Let f(x)=(x-3a)/(x-2b) for constants (a) and (b). If f(5)=0 and f(3) is undefined, what is the value of f(1/3)?

Question

After I worked it out, I got 8/5 (1 and 3/5).

Answer 1

If f(5) = 0, then 5 - 3a = 0. Solve for a

If f(3) is undefined, then 3 - 2b = 0. Solve for b.

Plug the values of a and b you get into f(x), then set x = 1/3 and compute f(1/3).