The no of real roots of the equation 2^(logbase2 (x^2-2x))=x-2

Answer 1

Just the left side:

log₂ (x² - 2x) is the exponent on 2 that results in x² - 2x. This is the meaning of "log"

Now log₂ (x² - 2x) is on 2, so the results is x² - 2x

x² - 2x = x - 2

How many real roots?