Shakil H.
asked 12/25/18sinA.sinB-cosA.cosB=0 proved that tanA+tanB=0
sinA.sinB-cosA.cosB=0 proved that tanA+tanB=0
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1 Expert Answer
tan (A+B) = (tan A + tan B)/(1-tan A tan B)
tan A + tan B = tan (A+B) (1 - tan A tan B)
Divide the hypothesis equation by cos A cos B to get
tan A tan B -1 = 0
Therefore tan A + tan B = 0
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Mark M.
Do you mean: (sin A)(sin B) - (cos A)(cos B)?12/25/18