2HgO=2Hg + O2 If 3.55mol HgO decomposes to creat 1.54mol O2 + 618g Hg .What is the percentage of this reaction?

Answer 1

2HgO ==> 2Hg + O2

You can approach this from the view of conservation of mass, or from the view of stoichiometry.

Conservation of mass approach:

mass HgO = 3.55 mole HgO x 217 g/mole = 770 g

mass of O2 = 1.54 moles x 32 g/mole = 49 g

mass of Hg = 618 g

mass of products = 618 g + 49 g = 667 g

% reaction = 667g/770 g (x100%) = 86.7%

Stoichiometry approach:

3.55 moles HgO x 1 mole O2/2 mole HgO = 1.775 moles O2 should be formed

1.54 moles/1.775 moles (x100%) = 86.7%