how to solve it

Question

Five times the smallest of three consecutive integers is 117 more than the sum of the integers. Find the integers.

Answer 1

let x = smallest of the three integers. Then, the consecutive integers are x, x+1 and x+2

5 times the smallest = 5x

117 more than the sum = 117 + x + x+1 + x+2

5x = 117 + x + x+1 + x+2

5x = 120 + 3x

2x = 120

x = 60

Integers are 60, 61 and 62