J.R. S. answered 12/15/18
Ph.D. University Professor with 10+ years Tutoring Experience
You'll need the specific heat of water to answer this question. The value is 4.184 J/g/deg
The equation that you'll want to use is q = mC∆T where
q = heat = ?
m = mass = 15.0 g
C = specific heat = 4.184 J/g/deg
∆T = change in temperature = 100º - 50º = 50º
q = (15.0 g)(4.184 J/g/deg)(50 deg)
q = 3138 joules = 3140 joules (to 3 significant figures)