J.R. S. answered 12/14/18
Ph.D. University Professor with 10+ years Tutoring Experience
2C4H10(g) + 13O2(g) ==> 8CO2(g) + 10H2O(g) ... K = 2.5x104
8CO2(g) + 10H2O(g) ==> 2C4H10(g) ... K = 1/2.5x104 = 4x10-5
Gnarls B.
asked 12/14/18If the combustion of C4H10(g) has K200°C = 2.5x104, find K200°C for the formation of C4H10(g) from its elements at these conditions
J.R. S. answered 12/14/18
Ph.D. University Professor with 10+ years Tutoring Experience
2C4H10(g) + 13O2(g) ==> 8CO2(g) + 10H2O(g) ... K = 2.5x104
8CO2(g) + 10H2O(g) ==> 2C4H10(g) ... K = 1/2.5x104 = 4x10-5
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