J.R. S. answered 12/11/18
Ph.D. University Professor with 10+ years Tutoring Experience
The equation you want is q = mCdeltaT
q = heat
m = mass = 350 g assuming 1 ml water = 1 g
C = specific heat of water = 4.184 J/g/degree
delta T = change in temperature = 5 - 1 = 4 degrees
Solving for q: q = (350g)(4.184 J/g/deg)(4 deg) = 5858 J