If you have 3.01 g of H2, how many grams of NH3 can be produced?

Answer 1

Write a balance equation:

N₂ + 3H₂ ==> 2NH₃

moles of H₂ used = 3.01 g x 1 mole/2 g = 1.505 moles

grams NH₃ produced = 1.505 moles H₂ x 2 moles NH₃/3 moles H₂ x 17 g/mole = 17.1 g