How many moles of KBr(119g/mol) are in 1000mL of a 2.38% (w/v) solution?

Question

How many moles of KBr(119g/mol) are in 1000mL of a 2.38% (w/v) solution? I don’t understand what the w/v is supposed to mean in this question. Or how to solve it.

Answer 1

2.38%(w/v) means 2.38 g/100 ml. Thus, 1000 ml = 23.8 g KBr

Moles KBr = 23.8 g x 1 mole/119 g = 0.200 moles