if 25 ml hcl acid with a concentration of .1234 M is neutralized by 23.45 mL of Ca(OH)2 what is the concentration of the base?

Question

if 25 ml hcl acid with a concentration of .1234 M is neutralized by 23.45 mL of Ca(OH)2 what is the concentration of the base?

Answer 1

2HCl + Ca(OH)₂ ==> CaCl₂ + 2H₂O ... balanced reaction

moles HCl present = 0.025 L x 0.1234 moles/L = 0.003085 moles HCl

moles Ca(OH)₂ required for neutralization = 0.003085 moles HCl x 1 mole Ca(OH)₂/2 moles HCl = 0.00154

Concentration of Ca(OH)₂ = 0.00154 moles/0.02345 L = 0.0658 M = 0.066 M