1. Write a balanced chemical equation, including physical state symbols, for the combustion of liquid decane into gaseous carbon dioxide and gaseous water

Question

1. suppose 0.490 kg of decane are burned in air at a pressure of exactly 1 atm and a temperature of 110 *C. Calculate the volume of carbon dioxide gas that is produced. Round your answer to 3 significant digits.

Answer 1

Decane is C₁₀H₂₂

2C₁₀H₂₂ (l) + 31O₂ (g) _==> 20CO₂(g)+ 22H₂O(g)... balanced eq

I’m not going to do the math for the second part, but will guide you.

Find moles decane: 0.490 kg x 1000g/kgx1 mol/molar mass decane

Convert moles decane to moles CO₂ using mole ratio in the balanced equation. moles decane x 10 = moles CO₂

To find volume CO₂ use PV = nRT and V = nRT/P

where n is moles just calculated, R is gas constant (0.0821), T is 383K, and p ia 1 atm. Volume will come out asliters.