How much methanol (CH3OH, in grams) can be formed from 58.7 g of hydrogen? Assume excess CO. CO(g) + 2H2(g) → CH3OH(g)

Answer 1

CO + 2H₂ ==> CH₃OH

Moles H₂ used = 58.7 g x 1 mole/2 g = 29.35 moles

Moles CH₃OH possible = 29.35 moles H₂ x 1 mol CH₃OH/2 mol H₂ = 14.68 moles

grams methanol = 14.68 moles x 32g/mole = 470 g (3 sig figs)