What is the specific heat (c) of the substance?

Question

A 53.11 g sample of a substance is initially at 27.4 °C. After absorbing 2741 J of heat, the temperature of the substance is 138.1 °C. What is the specific heat (c) of the substance?

Answer 1

q = mCdeltaT

q = 2741 J

m = 53.11 g

delta T = 138.1 - 27.4 = 110.7 degrees

C = specific heat

2741 = (53.11)(c)(110.7)

plug in the numbers and solve for c