How many mL OF .755 M H2SO4 solution is needed to react with 55 mL of 2.50 M KOH solution

Answer 1

H2SO4 + 2KOH ==> K2SO4 + 2H2O ... balanced equation

moles of KOH present = 0.055 L x 2.50 moles/L = 0.1375 moles KOH

moles H2SO4 needed = 0.1375 moles KOH x 1 mole H2SO4/2 moles KOH = 0.06875 moles H2SO4

mls H2SO4 needed: 0.755 moles H2SO4/L (x L) = 0.06875; x = 0.0911 L = 91.1 mls = 91 mls (2 sig. figs.)