Find the milliliters of 0.220 M KOH needed to neutralize 85.0 mL of 0.816 M H3PO4. Balance the chemical equation and show your work using one chain of conversion factors in your calculation.

Answer 1

Balance the equation and note the mole ratio between KOH and H₃PO₄:

3KOH + H₃PO₄ ==> K₃PO₄ + 3H₂0 (note mole ratio of 3 KOH to 1 H₃PO₄)

(85.0 ml H₃PO₄)(1L/1000 ml)(0.816 mol H₃PO₄/L)(3 mol KOH/mol H3PO4)(1 L/0.220 mol KOH)(1000 ml/L) = 946 mls