What volume (in L) of a 2.10 M NaOH solution is required to neutralize 0.30 mol of HCl?

Answer 1

The balanced equation is:;

NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l))

0.30 mol of HCl will require 0.30 mole of NaOH

Volume of NaOH needed: (2.10 mol/L)(x L) = 0.30 moles

x = 0.1429 L = 0.14 liters (to 2 significant figures)