length of a rectangle is 6 times its width area is 384yd^2 find perimeter

Answer 1

L = length

W = width

P = perimeter = 2L + 2W

A = area = L x W

L = 6W

L x W = 384

6W x W = 384

6W² = 384

W² = 64

W = 8 yds

L = 6W; L = 6 x 8 = 48 yds

P = 2L + 2W = (2x48) + (2x8) = 96 + 16 = 112 yds